document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=706825>Question 706825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I posted a problem several days ago, hoping to get some assistance for assignment due on Monday. Need help please.\r<BR>\n" );
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document.write( "A window in the shape of a rectangle with a semicircular top, (Norman window), .<BR>\n" );
document.write( "The height of the rectangular part is twice the base. If the base is 6 feet, what is the area?  I got 86.13 feet squared.\r<BR>\n" );
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document.write( "Then: Assume that the same window has a radius of 2 feet.We want the rectangular part of window to have same area as the semicircular top.What should the dimensions of the rectangle be? Please explain. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435425 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area will be the area of the rectangular part, plus the area of the semicircular part.<BR>\n" );
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document.write( "For the second part:<BR>\n" );
document.write( "If the radius is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2 ALIGN=MIDDLE  ALT=\"2\"   DISABLED_style= \"max-width:90%; height:auto;\" >ft, the diameter, which is also the width of the rectangle, is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A2ft=4 ALIGN=MIDDLE  ALT=\"2%2A2ft=4\"   DISABLED_style= \"max-width:90%; height:auto;\" >ft.<BR>\n" );
document.write( "That would be the base of the downwind.<BR>\n" );
document.write( "and if the height of the rectangular part is twice the base, then that height is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A4 ALIGN=MIDDLE  ALT=\"2%2A4\"   DISABLED_style= \"max-width:90%; height:auto;\" >feet=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8 ALIGN=MIDDLE  ALT=\"8\"   DISABLED_style= \"max-width:90%; height:auto;\" >feet.<BR>\n" );
document.write( "Then the area of the rectangular part is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284ft%29%288ft%29=32ft%5E2 ALIGN=MIDDLE  ALT=\"%284ft%29%288ft%29=32ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The area of half of a circle with radius <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2ft ALIGN=MIDDLE  ALT=\"2ft\"   DISABLED_style= \"max-width:90%; height:auto;\" > is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29pi%2A2%5E2ft%5E2=%281%2F2%294pi ALIGN=MIDDLE  ALT=\"%281%2F2%29pi%2A2%5E2ft%5E2=%281%2F2%294pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ft%5E2=2pi ALIGN=MIDDLE  ALT=\"ft%5E2=2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ft%5E2 ALIGN=MIDDLE  ALT=\"ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The total area is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=32ft%5E2%2B2pi ALIGN=MIDDLE  ALT=\"32ft%5E2%2B2pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ft%5E2=highlight%28%2832%2B2pi%29%29 ALIGN=MIDDLE  ALT=\"ft%5E2=highlight%28%2832%2B2pi%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ft%5E2 ALIGN=MIDDLE  ALT=\"ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >= approximately<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2832%2B6.28%29ft%5E2=highlight%2838.28%29ft%5E2 ALIGN=MIDDLE  ALT=\"%2832%2B6.28%29ft%5E2=highlight%2838.28%29ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > .<BR>\n" );
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document.write( "For the first part, a rectangle 3 feet by 6 feet would have an area of 72 square feet, and a semicircle with a 6 feet diameter (3 feet radius) would have an area of<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29pi%2A3%5E2ft%5E2=%289%2F2%29pi ALIGN=MIDDLE  ALT=\"%281%2F2%29pi%2A3%5E2ft%5E2=%289%2F2%29pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ft%5E2 ALIGN=MIDDLE  ALT=\"ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=14.14ft%5E2 ALIGN=MIDDLE  ALT=\"14.14ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "for a total area of approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=86.14ft%5E2 ALIGN=MIDDLE  ALT=\"86.14ft%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "That is what you found, aside from the rounding difference.<BR>\n" );
document.write( "(I used a more accurate version of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >, but I would get 86.13 too, If I used 3.14 por <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >).<BR>\n" );
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