document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=706832>Question 706832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radiator contains 7 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 45% antifreeze?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435396 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of fluid that needs to be drained and replaced with pure antifreeze\r<BR>\n" );
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document.write( "Now we know that the amount of pure antifreeze that exists before the mixture takes place(0.25(7-x)+x) has to equal the amount of pure antifreeze that exists after the mixture takes place(0.45*7), soooo:<BR>\n" );
document.write( "0.25(7-x)+x=0.45*7  simplify<BR>\n" );
document.write( "1.75-0.25x+x=3.15<BR>\n" );
document.write( "0.75x=3.15-1.75<BR>\n" );
document.write( "0.75x=1.4<BR>\n" );
document.write( "x=1.87 qts-------------ans\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "0.25(7-1.87)+1.87=3.15<BR>\n" );
document.write( "1.28+1.87=3.15<BR>\n" );
document.write( "3.15=3.15\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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