document.write( "Question 706800: Can you please help me solve this equation by completing the square.
\n" ); document.write( "-9x^+18x=16\r
\n" ); document.write( "\n" ); document.write( "Thank you!!
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Algebra.Com's Answer #435384 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: COMPLETING THE SQUARE solver for quadratics
Read this lesson on completing the square by prince_abubu, if you do not know how to complete the square.
Let's convert \"-9x%5E2%2B18x%2B-16=0\" to standard form by dividing both sides by -9:
\n" ); document.write( "We have: \"1x%5E2%2B-2x%2B1.77777777777778=0\". \n" ); document.write( "What we want to do now is to change this equation to a complete square \"%28x%2Bsomenumber%29%5E2+%2B+othernumber\". How can we find out values of somenumber and othernumber that would make it work?
\n" ); document.write( "Look at \"%28x%2Bsomenumber%29%5E2\": \"%28x%2Bsomenumber%29%5E2+=+x%5E2%2B2%2Asomenumber%2Ax+%2B+somenumber%5E2\". Since the coefficient in our equation \"1x%5E2%2Bhighlight_red%28+-2%29+%2A+x%2B1.77777777777778=0\" that goes in front of x is -2, we know that -2=2*somenumber, or \"somenumber+=+-2%2F2\". So, we know that our equation can be rewritten as \"%28x%2B-2%2F2%29%5E2+%2B+othernumber\", and we do not yet know the other number.
\n" ); document.write( "We are almost there. Finding the other number is simply a matter of not making too many mistakes. We need to find 'other number' such that \"%28x%2B-2%2F2%29%5E2+%2B+othernumber\" is equivalent to our original equation \"1x%5E2%2B-2x%2Bhighlight_green%28+1.77777777777778+%29=0\".
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\n" ); document.write( " The highlighted red part must be equal to 1.77777777777778 (highlighted green part).
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\n" ); document.write( " \"-2%5E2%2F4+%2B+othernumber+=+1.77777777777778\", or \"othernumber+=+1.77777777777778--2%5E2%2F4+=+0.777777777777778\".
\n" ); document.write( "So, the equation converts to \"%28x%2B-2%2F2%29%5E2+%2B+0.777777777777778+=+0\", or \"%28x%2B-2%2F2%29%5E2+=+-0.777777777777778\".
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\n" ); document.write( " Our equation converted to a square \"%28x%2B-2%2F2%29%5E2\", equated to a number (-0.777777777777778).
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\n" ); document.write( " There is no number whose square can be negative. So, there is no solution to this equation
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