document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=706706>Question 706706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice a number decreased by 3 is less than 12. One more than three times the same number is greater than 20. Find the number.<BR>\n" );
document.write( "a) 5<BR>\n" );
document.write( "b) 6<BR>\n" );
document.write( "c) 7<BR>\n" );
document.write( "d) 8<BR>\n" );
document.write( "e) 9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435347 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Twice a number decreased by 3 is less than 12. One more than three times the same number is greater than 20. Find the number.<BR>\n" );
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document.write( "Let the number be \"x\":<BR>\n" );
document.write( "2x-3 < 12<BR>\n" );
document.write( "3x+1 > 20<BR>\n" );
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document.write( "Modify each inequality<BR>\n" );
document.write( "x < 15/2 = 7.5<BR>\n" );
document.write( "x > 19/3 > 6.333..<BR>\n" );
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document.write( "Ans: 7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================<BR>\n" );
document.write( "a) 5<BR>\n" );
document.write( "b) 6<BR>\n" );
document.write( "c) 7<BR>\n" );
document.write( "d) 8<BR>\n" );
document.write( "e) 9<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );