document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62710>Question 62710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by addition.<BR>\n" );
document.write( "	5x – 3y = 13<BR>\n" );
document.write( "	4x – 3y = 11<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43534 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x – 3y = 13<BR>\n" );
document.write( "4x – 3y = 11\r<BR>\n" );
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document.write( "Subtract the second equation from the first to get 1x = 2. Substitute x=2 into the first equation to get<BR>\n" );
document.write( "5 x 2 - 3y = 13<BR>\n" );
document.write( "10 - 3y = 13 Subtract 10 from each side<BR>\n" );
document.write( "10 - 3y - 10 = 13 - 10<BR>\n" );
document.write( "-3y = 3<BR>\n" );
document.write( "So y = -1\r<BR>\n" );
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document.write( "x = 2 and y = -1<BR>\n" );
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