document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62709>Question 62709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference of two numbers is 27.  The second is 1 less than 3 times the first.  What are the two numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43533 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Number 1 = x so the second number will be = 3x-1 (ie 1 less than three times the first).<BR>\n" );
document.write( "Difference = Number 2 - Number 1<BR>\n" );
document.write( "27 = 3x - 1 - x<BR>\n" );
document.write( "27 = 2x - 1 Add 1 to each side of the equation<BR>\n" );
document.write( "27 + 1 = 2x - 1 + 1<BR>\n" );
document.write( "28 = 2x Divide each side by 2 <BR>\n" );
document.write( "14 = x<BR>\n" );
document.write( "If the first number is 14 then the second number must be 41. </SPAN>\n" );
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