document.write( "Question 706614: sin(theta) - (root 3)cos(theta) = 1 \n" ); document.write( "
Algebra.Com's Answer #435313 by lwsshak3(11628)\"\" \"About 
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sin(theta) - (root 3)cos(theta) = 1
\n" ); document.write( "For (0,2π)
\n" ); document.write( "sinx-√3cosx=1
\n" ); document.write( "sinx-1=√3cosx
\n" ); document.write( "square both sides
\n" ); document.write( "sin^2x-2sinx+1=3cos^2x=3(1-sin^2x)=3-3sin^2x
\n" ); document.write( "4sin^2x-2sinx+2=0
\n" ); document.write( "2sin^2x-sinx+1=0
\n" ); document.write( "(2sinx+1)(sinx-1)=0
\n" ); document.write( "..
\n" ); document.write( "2sinx+1=0
\n" ); document.write( "sinx=-1/2
\n" ); document.write( "x=7π/6, 11π/6 (in quadrants III and IV where sin<0)
\n" ); document.write( "or
\n" ); document.write( "sinx-1=0
\n" ); document.write( "sinx=1
\n" ); document.write( "x=π/2
\n" ); document.write( " \n" ); document.write( "
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