document.write( "Question 706613: (sec 3(theta))/2 = -2 \n" ); document.write( "

Algebra.Com's Answer #435309 by lwsshak3(11628) $\"\"$ $\"About$

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(sec 3(theta))/2 = -2
\n" ); document.write( "(sec 3x)/2=-2
\n" ); document.write( "sec 3x=-4
\n" ); document.write( "cos 3x=-1/4
\n" ); document.write( "3x≈104.48º
\n" ); document.write( "x≈34.83º \n" ); document.write( "

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