document.write( "Question 706635: Not sure if in correct area for help, but here goes:\r
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document.write( "I have two problems needing help with quickly.\r
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document.write( "A man is building a concrete patio 29 feet wide, 30 feet long, 6 inches thick. Mixed concrete is sold by the cubic yard. How many cubic yards needed for project? (must convert cubic feet into cubic yards to solve) HELP!!!\r
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document.write( "A cone with radius 5 inches, height 12 inches, which causes volume to increase more, increasing radius or height? Explain. \n" );
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Algebra.Com's Answer #435300 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! 1 yard = 3 feet. \n" ); document.write( "If you are using feet and yards in volume then you must convert for all three dimensions. \n" ); document.write( "1 ft * 1 ft * 1 ft = 1 ft^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1ft*((1yd/3ft))*1ft*((1yd/3ft))*1ft*((1yd/3ft))= 1 yd^3 per 3^3 ft^3, \n" ); document.write( "One cubic yard is 27 cubic feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Patio volume: 29ft*30ft*(1/2)ft., how many cubic yards?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |