document.write( "Question 706402: \r
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document.write( "a invest 10% more than b, b invest 10% less than c, what did c invest if total investement is 5780? \n" );
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Algebra.Com's Answer #435245 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! A=1.1B \n" ); document.write( "B=.9C \n" ); document.write( "A+B=C=5780 \n" ); document.write( "1.1B+.9C+C=5780 \n" ); document.write( "1.1(.9C)+.9C+C=5780 \n" ); document.write( ".99C+.9C+C=5780 \n" ); document.write( "2.89C=5780 \n" ); document.write( "C=5780/2.89 \n" ); document.write( "C=$2000 AMOUNT C INVESTED. \n" ); document.write( "PROOF: \n" ); document.write( "B=.9*2000=1800 B INVESTMENT. \n" ); document.write( "A=1.1*1800=1980 A INVESTMENT. \n" ); document.write( "1980+1890+2000=5780 \n" ); document.write( "5780=5780 \n" ); document.write( " |