document.write( "Question 62693This question is from textbook Beginning Algebra
\n" ); document.write( ": Add. Express your answer in simplest form.\r
\n" ); document.write( "\n" ); document.write( "x-13 + 3x-3
\n" ); document.write( "---- -----
\n" ); document.write( "x^2-x-12 x^2-x-12\r
\n" ); document.write( "\n" ); document.write( "the denominator is the same, so I'm sure this is simple and I am making harder than it is.
\n" ); document.write( "

Algebra.Com's Answer #43523 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x-13 + 3x-3
\n" ); document.write( "---- -----
\n" ); document.write( "x^2-x-12 x^2-x-12
\n" ); document.write( "---------------------------
\n" ); document.write( "The denominators are the same, so add the numerators, as follows:
\n" ); document.write( "----------
\n" ); document.write( "[4x-16]/[x^2-x-12]
\n" ); document.write( "=[4(x-4)]/[(x-4)(x+3)]
\n" ); document.write( "Cancel the (x-4) factors to get:
\n" ); document.write( "=4/(x+3)
\n" ); document.write( "---------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );