document.write( "Question 62693This question is from textbook Beginning Algebra
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document.write( ": Add. Express your answer in simplest form.\r
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document.write( "x-13 + 3x-3
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document.write( "---- -----
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document.write( "x^2-x-12 x^2-x-12\r
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document.write( "the denominator is the same, so I'm sure this is simple and I am making harder than it is. \n" );
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Algebra.Com's Answer #43523 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x-13 + 3x-3 \n" ); document.write( "---- ----- \n" ); document.write( "x^2-x-12 x^2-x-12 \n" ); document.write( "--------------------------- \n" ); document.write( "The denominators are the same, so add the numerators, as follows: \n" ); document.write( "---------- \n" ); document.write( "[4x-16]/[x^2-x-12] \n" ); document.write( "=[4(x-4)]/[(x-4)(x+3)] \n" ); document.write( "Cancel the (x-4) factors to get: \n" ); document.write( "=4/(x+3) \n" ); document.write( "--------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |