document.write( "Question 62452: Find the equation of the plane containing the line L1, and parallel to the line L2, where:\r
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document.write( "L1: (x,y,z) = (-2,-1,1) + t (-3,0,2).\r
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document.write( "L2: is the intersection of the planes 2x-2y-3z=-5 and 1x-3y-3z=-3 \r
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document.write( "Write your answer in the form -4x+By+Cz=D, and give the values of B, C and D as your answer.
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Algebra.Com's Answer #43517 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Find the equation of the plane=P SAY, containing the line L1, and parallel to the line L2, where: \n" ); document.write( "L1: (x,y,z) = (-2,-1,1)(Q SAY) + t (-3,0,2). \n" ); document.write( "L2: is the intersection of the planes 2x-2y-3z=-5 and 1x-3y-3z=-3 \n" ); document.write( "Write your answer in the form -4x+By+Cz=D, and give the values of B, C and D as your answer. \n" ); document.write( "EQUATION OF P THROUGH Q IS \n" ); document.write( "A(X+2)+B(Y+1)+C(Z-1)=0..............................1 \n" ); document.write( "DRS OF NORMAL ARE A,B,C.........NORMAL PERPENDICULAR TO L1 \n" ); document.write( "-3A+2C=0........A=2C/3 ...............2 \n" ); document.write( "IF DRS OF L2 ARE L,M,N THEN \n" ); document.write( "2L-2M-3N=0...............3 \n" ); document.write( "L-3M-3N=0.................4 \n" ); document.write( "|-2,-3| \n" ); document.write( "|-3,-3|=6-9=-3 \n" ); document.write( "|-3,2| \n" ); document.write( "|-3,1|=3 \n" ); document.write( "|2,-2| \n" ); document.write( "|1,-3|=-4 \n" ); document.write( "L:M:N=-3:3:-4 \n" ); document.write( "HENCE \n" ); document.write( "-3A+3B-4C=0...................5 \n" ); document.write( "-3*2C/3 +3B-4C=0 \n" ); document.write( "3B=6C \n" ); document.write( "B=2C \n" ); document.write( "A=2C/3.....OR.....TAKING C = 6....A=4,B=12 \n" ); document.write( "EQN OF PLANE IS \n" ); document.write( "4(X+2)+12(Y+1)+6(Z-1)=0 \n" ); document.write( "-4X-12Y-6Z=14 \n" ); document.write( " |