document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=706417>Question 706417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular room is 3 feet longer than twice the width. If the room's perimeter is 210 feet, what are the room's dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435142 by </B><A HREF=/tutors/aboutme.mpl?userid=redpeace><B>redpeace(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=redpeace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Known: Perimeter=210 feet<BR>\n" );
document.write( "Length= 2*n+3<BR>\n" );
document.write( "Width= n\r<BR>\n" );
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document.write( "Equation = Perimeter= length + width\r<BR>\n" );
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document.write( "210= 2*n+3 + n<BR>\n" );
document.write( "210= 2n+3+n<BR>\n" );
document.write( "210=3n +3 <BR>\n" );
document.write( "210-3=3n<BR>\n" );
document.write( "207=3n (divide both sides by 3)<BR>\n" );
document.write( "207/3 = 3n/3\r<BR>\n" );
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document.write( "69=n\r<BR>\n" );
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document.write( "Length - 2*n +3 (2*69 +3) = 138+3 = 141 ft.\r<BR>\n" );
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document.write( "Width = 69 ft.\r<BR>\n" );
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document.write( "Perimeter - 141+69 = 210<BR>\n" );
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