document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704751>Question 704751</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Every year, a tree bears 3 more fruits than it did the previous year. If it bore 12 fruits in 1995, how many fruits would it bear by 2010?\r<BR>\n" );
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document.write( "Show your solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #435123 by </B><A HREF=/tutors/aboutme.mpl?userid=filboi><B>filboi(35)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=filboi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=435123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's look at the pattern first.<BR>\n" );
document.write( "Year 1: 1995 => 12 + 3(0) = 12<BR>\n" );
document.write( "Year 2: 1996 => 12 + 3(1) = 15<BR>\n" );
document.write( "Year 3: 1997 => 12 + 3(2) = 18<BR>\n" );
document.write( "Year 4: 1998 => 12 + 3(3) = 21<BR>\n" );
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document.write( "Year16: 2010 => 12 + 3(15) = 57  \r<BR>\n" );
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document.write( "You will notice that the multiplier() is always less than 1 of the year.\r<BR>\n" );
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document.write( "Year Y: 12 + 3(Y-1)\r<BR>\n" );
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document.write( "You will also notice that 2010 is year 16 and not 15.\r<BR>\n" );
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