document.write( "Question 62699: 1. Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number.
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document.write( "x + 7 – 8x – 9 ≥ 3(x – 7)\r
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Algebra.Com's Answer #43510 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Solve for x. Collect xs on the LEFT side. The solution should be presented with x first, the correct inequality symbol, then the number. \n" ); document.write( "That's the way to do it: \n" ); document.write( ": \n" ); document.write( "x + 7 – 8x – 9 ≥ 3(x – 7) \n" ); document.write( ": \n" ); document.write( "mult what's in brackets: \n" ); document.write( "x + 7 – 8x – 9 ≥ 3x – 21) \n" ); document.write( ": \n" ); document.write( "Combine like terms: \n" ); document.write( "x - 8x + 7 - 9 ≥ 3x – 21 \n" ); document.write( "-7x + -2 ≥ 3x – 21 \n" ); document.write( ": \n" ); document.write( "Add 2 and subtract 3x from both sides: \n" ); document.write( "-7x - 3x => -21 + 2 \n" ); document.write( "-10x => -19 \n" ); document.write( ": \n" ); document.write( "Get rid of the neg x, mult eq by -1, this reverses the inequality sign \n" ); document.write( "+10x =< +19 \n" ); document.write( "x =< 19/10 \n" ); document.write( " \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |