document.write( "Question 706282: Hey guys, this question is related to applications of calculus (I couldn't find the section.
\n" );
document.write( "So, the question is as follows:\r
\n" );
document.write( "\n" );
document.write( "A rectangular block, the length of whose base is twice the width has a total surface area of 300cm^2. Find the dimensions of the block if it is of maximum volume. \r
\n" );
document.write( "\n" );
document.write( "Thank You \n" );
document.write( "
Algebra.Com's Answer #435097 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangular block, the length of whose base is twice the width has a total surface area of 300cm^2. \n" ); document.write( " Find the dimensions of the block if it is of maximum volume. \n" ); document.write( ": \n" ); document.write( "Max volume will be when the larger dimension is the square sides \n" ); document.write( "Let the squared base = 2w by 2w, the third dimension = w \n" ); document.write( ": \n" ); document.write( "Surface area then \n" ); document.write( "2(2w*2w) + 4(2w*w) = 300 \n" ); document.write( "8w^2 + 8w^2 = 300 \n" ); document.write( "16w^2 = 300 \n" ); document.write( "w^2 = 300/16 \n" ); document.write( "w^2 = 18.75 \n" ); document.write( "w = \n" ); document.write( "w ~ 4.33 cm is width and 8.66 cm the sides of the square base \n" ); document.write( ": \n" ); document.write( "Dimensions for max volume 8.66 by 8.66 by 4.33 \n" ); document.write( " |