document.write( "Question 706282: Hey guys, this question is related to applications of calculus (I couldn't find the section.
\n" ); document.write( "So, the question is as follows:\r
\n" ); document.write( "\n" ); document.write( "A rectangular block, the length of whose base is twice the width has a total surface area of 300cm^2. Find the dimensions of the block if it is of maximum volume. \r
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Algebra.Com's Answer #435097 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular block, the length of whose base is twice the width has a total surface area of 300cm^2.
\n" ); document.write( " Find the dimensions of the block if it is of maximum volume.
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\n" ); document.write( "Max volume will be when the larger dimension is the square sides
\n" ); document.write( "Let the squared base = 2w by 2w, the third dimension = w
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\n" ); document.write( "Surface area then
\n" ); document.write( "2(2w*2w) + 4(2w*w) = 300
\n" ); document.write( "8w^2 + 8w^2 = 300
\n" ); document.write( "16w^2 = 300
\n" ); document.write( "w^2 = 300/16
\n" ); document.write( "w^2 = 18.75
\n" ); document.write( "w = \"sqrt%2818.75%29\"
\n" ); document.write( "w ~ 4.33 cm is width and 8.66 cm the sides of the square base
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\n" ); document.write( "Dimensions for max volume 8.66 by 8.66 by 4.33
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