document.write( "Question 706282: Hey guys, this question is related to applications of calculus (I couldn't find the section.
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document.write( "So, the question is as follows:\r
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document.write( "A rectangular block, the length of whose base is twice the width has a total surface area of 300cm^2. Find the dimensions of the block if it is of maximum volume. \r
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document.write( "Thank You \n" );
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Algebra.Com's Answer #435095 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! x length, y width, z height. \n" ); document.write( "volume of the box would be xyz.\r \n" ); document.write( "\n" ); document.write( "x=2y as given, so volume is 2*y*y*z or volume \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Surface area was given as 300 cubic units. Accounting for the lengths measurements, \n" ); document.write( " \n" ); document.write( "4y^2+2yz+4yz=300 \n" ); document.write( "...and few more steps... \n" ); document.write( "z=(300-4y^2)/(2y+4y) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Back to the volume formula, \n" ); document.write( " \n" ); document.write( "v=2y^2(2/3)(75-y^2)/y \n" ); document.write( "v=... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The task to do now is the maximize v as a function of width y. Differentiate v with respect to y. \n" ); document.write( "You then simply calculate x from knowing how x and y were given. Then you may need to use the z formula found above to caclulate z. \n" ); document.write( " |