document.write( "Question 706308: A boat, which moves at 18 miles per hour in water without a current, goes 80 miles upstream and 80 miles back again in 9 hours. Find the speed of the current to the nearest tenth.\r
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document.write( "I am very confused on how to work out this problem... \n" );
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Algebra.Com's Answer #435072 by stanbon(75887) ![]() You can put this solution on YOUR website! A boat, which moves at 18 miles per hour in water without a current, goes 80 miles upstream and 80 miles back again in 9 hours. Find the speed of the current to the nearest tenth. \n" ); document.write( "---- \n" ); document.write( "Let current speed be \"c\" . \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "Upstream DATA: \n" ); document.write( "distance = 80 miles ; rate = 18-c mph ; time = d/r = 80/(18-c) hrs. \n" ); document.write( "--------------------------------- \n" ); document.write( "Downstream DATA: \n" ); document.write( "distance = 80 miles ; rate = 19+c mph ; time = d/r = 80/(18+c) hrs \n" ); document.write( "---------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time up + time down = 9 hrs \n" ); document.write( "80/(18-c) + 80/(18+c) = 9 \n" ); document.write( "----- \n" ); document.write( "80(18+c) + 80(18-c) = 9(18-c)(18+c) \n" ); document.write( "--------------------------------------------- \n" ); document.write( "2*80*18 = 9(324-c^2) \n" ); document.write( "320 = 324-c^2 \n" ); document.write( "c^2 = 4 \n" ); document.write( "c = 2 mph (speed of the current) \n" ); document.write( "------------------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |