document.write( "Question 706308: A boat, which moves at 18 miles per hour in water without a current, goes 80 miles upstream and 80 miles back again in 9 hours. Find the speed of the current to the nearest tenth.\r
\n" ); document.write( "\n" ); document.write( "I am very confused on how to work out this problem...
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Algebra.Com's Answer #435072 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A boat, which moves at 18 miles per hour in water without a current, goes 80 miles upstream and 80 miles back again in 9 hours. Find the speed of the current to the nearest tenth.
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\n" ); document.write( "Let current speed be \"c\" .
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 80 miles ; rate = 18-c mph ; time = d/r = 80/(18-c) hrs.
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 80 miles ; rate = 19+c mph ; time = d/r = 80/(18+c) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "time up + time down = 9 hrs
\n" ); document.write( "80/(18-c) + 80/(18+c) = 9
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\n" ); document.write( "80(18+c) + 80(18-c) = 9(18-c)(18+c)
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\n" ); document.write( "2*80*18 = 9(324-c^2)
\n" ); document.write( "320 = 324-c^2
\n" ); document.write( "c^2 = 4
\n" ); document.write( "c = 2 mph (speed of the current)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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