document.write( "Question 706087: (4/3)to the 3rd power divided by 2-2/3\r
\n" ); document.write( "\n" ); document.write( "tried several different ways, I know the answer is 16/9 but don't know how to get it.\r
\n" ); document.write( "\n" ); document.write( "I tried.\r
\n" ); document.write( "\n" ); document.write( "64/27 x -4/3 then I flipped to -3/4\r
\n" ); document.write( "\n" ); document.write( "came up with 61/23\r
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Algebra.Com's Answer #434993 by josgarithmetic(39627)\"\" \"About 
You can put this solution on YOUR website!
You expected 16/9, so this is one way to understand what you are actually given:\r
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\n" ); document.write( "\n" ); document.write( "(4/3)^3 DIVIDED BY (2-2/3), or in complicated fractional form,
\n" ); document.write( "\"%28%284%2F3%29%5E3%29%2F%282-2%2F3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"%28%284%5E3%29%2F%283%5E3%29%29%2F%28%286-2%29%2F3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"%28%284%5E3%29%2F%283%5E3%29%29%2F%284%2F3%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"%28%284%5E3%29%2F%283%5E3%29%29%2A%283%2F4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"%284%5E2%29%2F%283%5E2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"16%2F9\"
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