document.write( "Question 706055: Hal is doing a chemistry experiment that calls for a 30% solution of copper sulfate. Hal has 40mL of a 25% solution. How many milliliters of a 60% solution should Hal add to obtain the required 30% solution?
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Algebra.Com's Answer #434987 by lwsshak3(11628)\"\" \"About 
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Hal is doing a chemistry experiment that calls for a 30% solution of copper sulfate. Hal has 40mL of a 25% solution. How many milliliters of a 60% solution should Hal add to obtain the required 30% solution?
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\n" ); document.write( "let x=amt of 60% solution to be added
\n" ); document.write( "25%*40+60%x=30%(40+x)
\n" ); document.write( ".25*40+.6x=12+.3x
\n" ); document.write( "10+.6x=12+.3x
\n" ); document.write( ".3x=2
\n" ); document.write( "3x=20
\n" ); document.write( "x=20/3
\n" ); document.write( "amt of 60% solution to be added=20/3 ml
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