document.write( "Question 706119: graph x=(y+1)^2-4 \n" ); document.write( "
Algebra.Com's Answer #434984 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
graph x=(y+1)^2-4
\n" ); document.write( "This is an equation of a parabola that opens right.
\n" ); document.write( "Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given equation: x=(y+1)^2-4
\n" ); document.write( "rewrite: (y+1)^2=(x+4)
\n" ); document.write( "vertex: (-4,-1)
\n" ); document.write( "y-intercepts
\n" ); document.write( "set x=0
\n" ); document.write( "(y+1)^2=4
\n" ); document.write( "y+1=±√4=±2
\n" ); document.write( "y=-1±2
\n" ); document.write( "y=-3 and 1
\n" ); document.write( "See graph below:
\n" ); document.write( "y=-1+(x+4)^.5
\n" ); document.write( " \n" ); document.write( "
\n" );