document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=706112>Question 706112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this growth and decay problem it reads: A material decays at a rate of 1.1% per year. If you start with 250 grams of the material, in how many years will there be 100 grams remaining </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434982 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Every time period, the material lost 1.1% of what it had in the beginning of the period.  Meaning that it becomes 100-1.1=98.9 percent of its strength as each time period passes.  \r<BR>\n" );
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document.write( "Starting at any amount A, the first period makes A*0.989, the second time period means that there is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2A0.989%2A0.989 ALIGN=MIDDLE  ALT=\"A%2A0.989%2A0.989\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and then for any number of time periods, the quantity remaining will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2A%280.989%29%5Et ALIGN=MIDDLE  ALT=\"A%2A%280.989%29%5Et\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where t is the number of time periods which pass.\r<BR>\n" );
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document.write( "If <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5B0%5D ALIGN=MIDDLE  ALT=\"A%5B0%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the initial amount to start, the <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bt%5D ALIGN=MIDDLE  ALT=\"A%5Bt%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the amount remaining after t time.  t can be in years, in this example.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bt%5D=A%5B0%5D%2A%280.989%29%5Et ALIGN=MIDDLE  ALT=\"A%5Bt%5D=A%5B0%5D%2A%280.989%29%5Et\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "If you want what t for starting with 250 grams and having 100 grams remaining,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100=250%2A0.989%5Et ALIGN=MIDDLE  ALT=\"100=250%2A0.989%5Et\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F5=0.989%5Et ALIGN=MIDDLE  ALT=\"2%2F5=0.989%5Et\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%282%2F5%29=t%2Aln%280.989%29 ALIGN=MIDDLE  ALT=\"ln%282%2F5%29=t%2Aln%280.989%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t=%28ln%282%2F5%29%29%2F%28ln%280.989%29%29 ALIGN=MIDDLE  ALT=\"t=%28ln%282%2F5%29%29%2F%28ln%280.989%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Seems to be t=82.8 years  or t=83 years. </SPAN>\n" );
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