document.write( "Question 706005: how can i find the focus/foci and vertex/vertices\r
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document.write( "x^2-4y^2-2x+16y=20\r
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document.write( "this is how far i have gotten, but i am not sure if it is right so far\r
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document.write( "x^2-4y^2-2x+16y=20
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document.write( "(x^2-2x+1)-4(y^2+4y+4)=20+1+4
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document.write( "(x-1)^2/25-4(y+4)^2/25=25/25
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document.write( "(x-1)^2/25-4(y+4)^2/25=1\r
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document.write( "please help. thank you. \n" );
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Algebra.Com's Answer #434916 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note the -4 coefficient OUTSIDE the parentheses so the 1st degree y term has to have a coefficient of -4 (-4 times -4 is +16), then in order to complete the square inside the parentheses you need a +4, and +4 times -4 is -16. What you add to the left must be added to the right, hence the -16 in the RHS.\r \n" ); document.write( "\n" ); document.write( "From there:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Can you take it from there?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |