document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=705960>Question 705960</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Germaine walks at the rate of 10 feet every five seconds while Nolan walks at the rate of 15 feet every five seconds. If Germaine has a head start of 25 feet, after how many seconds will they be at the same spot? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434899 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434899\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Germaine walks at the rate of 10 feet every five seconds while Nolan walks at the rate of 15 feet every five seconds. If Germaine has a head start of 25 feet, after how many seconds will they be at the same spot?<BR>\n" );
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document.write( "let x=Additional distance Germain walked after a distance of 25 ft<BR>\n" );
document.write( "x+25=Distance Nolan walked to catch up to Germaine<BR>\n" );
document.write( "Walking speed of Germaine: 10/5=2ft/sec<BR>\n" );
document.write( "Walking speed of Nolan: 15/5=3ft/sec<BR>\n" );
document.write( "travel time=distance/speed<BR>\n" );
document.write( "x/2=(x+25)/3<BR>\n" );
document.write( "3x=2x+50<BR>\n" );
document.write( "x=50<BR>\n" );
document.write( "x/2=25<BR>\n" );
document.write( "Nolan and Germaine will they be at the same spot in 25 sec </SPAN>\n" );
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