document.write( "Question 705911: twice the smallest of three consecutive odd integers is seven more than the largest. \n" ); document.write( "
Algebra.Com's Answer #434867 by stanbon(75887)\"\" \"About 
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twice the smallest of three consecutive odd integers is seven more than the largest.
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\n" ); document.write( "1st: 2x-1
\n" ); document.write( "2nd: 2x+1
\n" ); document.write( "3rd: 2x+3
\n" ); document.write( "-------
\n" ); document.write( "Equation:
\n" ); document.write( "2(2x-1) = 2x+3+7
\n" ); document.write( "------
\n" ); document.write( "4x-2 = 2x+10
\n" ); document.write( "2x = 12
\n" ); document.write( "x = 6
\n" ); document.write( "----
\n" ); document.write( "1st: 2x-1 = 11
\n" ); document.write( "2nd: 2x+1 = 13
\n" ); document.write( "3rd: 2x+3 = 15
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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