document.write( "Question 705911: twice the smallest of three consecutive odd integers is seven more than the largest. \n" ); document.write( "
Algebra.Com's Answer #434867 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! twice the smallest of three consecutive odd integers is seven more than the largest. \n" ); document.write( "---- \n" ); document.write( "1st: 2x-1 \n" ); document.write( "2nd: 2x+1 \n" ); document.write( "3rd: 2x+3 \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "2(2x-1) = 2x+3+7 \n" ); document.write( "------ \n" ); document.write( "4x-2 = 2x+10 \n" ); document.write( "2x = 12 \n" ); document.write( "x = 6 \n" ); document.write( "---- \n" ); document.write( "1st: 2x-1 = 11 \n" ); document.write( "2nd: 2x+1 = 13 \n" ); document.write( "3rd: 2x+3 = 15 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " \n" ); document.write( " |