document.write( "Question 705779: Last year, Jodi invested 10,000, part at .06 annual interest and the rest .08 annual interest. If she received $760 in interest at the end of the year, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #434786 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Last year, Jodi invested 10,000, part at .06 annual interest and the rest .08 annual interest. If she received $760 in interest at the end of the year, how much did she invest at each rate? \n" ); document.write( "------- \n" ); document.write( "Equations: \n" ); document.write( "Quantity Equation: x + y = 10,000 \n" ); document.write( "Interest Equation:6x + 8y = 76000 \n" ); document.write( "------- \n" ); document.write( "Modify: \n" ); document.write( "6x + 6y = 6*10,000 \n" ); document.write( "6x + 8y = 76000 \n" ); document.write( "--------------------- \n" ); document.write( "Subtract to solve for \"y\": \n" ); document.write( "2y = 16000 \n" ); document.write( "y = $8000 (amt. invested at 8%) \n" ); document.write( "---- \n" ); document.write( "x = $2000 (amt. invested at 6% \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |