document.write( "Question 705779: Last year, Jodi invested 10,000, part at .06 annual interest and the rest .08 annual interest. If she received $760 in interest at the end of the year, how much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #434786 by stanbon(75887)\"\" \"About 
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Last year, Jodi invested 10,000, part at .06 annual interest and the rest .08 annual interest. If she received $760 in interest at the end of the year, how much did she invest at each rate?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Equation: x + y = 10,000
\n" ); document.write( "Interest Equation:6x + 8y = 76000
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\n" ); document.write( "Modify:
\n" ); document.write( "6x + 6y = 6*10,000
\n" ); document.write( "6x + 8y = 76000
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\n" ); document.write( "Subtract to solve for \"y\":
\n" ); document.write( "2y = 16000
\n" ); document.write( "y = $8000 (amt. invested at 8%)
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\n" ); document.write( "x = $2000 (amt. invested at 6%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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