document.write( "Question 705761: Find the dimentions of a rectangle whose lenth is one foot longer than twice its width and whose perameter is 20 feet. \n" ); document.write( "

Algebra.Com's Answer #434774 by Stitch(470) $\"\"$ $\"About$

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\n" ); document.write( "Equation 1: $\"L+=+2W+%2B+1\"$
\n" ); document.write( "Equation 2: $\"P+=+2L+%2B+2W\"$ (The perimeter of a rectangle
\n" ); document.write( "P = 20
\n" ); document.write( "-----------------------------
\n" ); document.write( "Since equation 1 is already solved for L, plug (2W + 1) into equation 2 for L
\n" ); document.write( "Equation 2: $\"P+=+2L+%2B+2W\"$
\n" ); document.write( " $\"20+=+2%2A%282W+%2B+1%29+%2B+2W\"$
\n" ); document.write( "Multiply the 2 through
\n" ); document.write( " $\"20+=+4W+%2B+2+%2B+2W\"$
\n" ); document.write( "Combine like terms
\n" ); document.write( " $\"20+=+6W+%2B+2\"$
\n" ); document.write( "Subtract 2 from both sides
\n" ); document.write( " $\"18+=+6W\"$
\n" ); document.write( "Divide both sides by 6
\n" ); document.write( " $\"highlight%283+=+W%29\"$
\n" ); document.write( "Now plug 3 into equation 1 for W
\n" ); document.write( "Equation 1: $\"L+=+2W+%2B+1\"$
\n" ); document.write( " $\"L+=+2%2A%283%29+%2B+1\"$
\n" ); document.write( " $\"L+=+6+%2B+1\"$
\n" ); document.write( " $\"highlight_green%28L+=+7%29\"$ \n" ); document.write( "

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