document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=705759>Question 705759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a 3 degree drop in tempature for every 1'000 feet that an airplane climbs in the sky. If the tempature on the ground is 50 degrees, what will be the tempature when the plane reaches an altitude of 24,000 feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434773 by </B><A HREF=/tutors/aboutme.mpl?userid=Stitch><B>Stitch(470)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Stitch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 24,000ft / 1000ft = 24<BR>\n" );
document.write( "24 * 3 degrees =  72<BR>\n" );
document.write( "50 degrees - 72 degrees = -22 degrees<BR>\n" );
document.write( "At 24,000 the temperature is -22 degrees </SPAN>\n" );
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