document.write( "Question 62669This question is from textbook
\n" ); document.write( ": Hello \r
\n" ); document.write( "\n" ); document.write( "For the life of me, i get different results with the substitution method, \r
\n" ); document.write( "\n" ); document.write( "the textbook answer is -3, 2 Independent for the following:\r
\n" ); document.write( "\n" ); document.write( "y = 3x + 11
\n" ); document.write( "3x + 3y = 0\r
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\n" ); document.write( "\n" ); document.write( "i come out with y= 11/4, x=11/4?????
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Algebra.Com's Answer #43470 by uma(370)\"\" \"About 
You can put this solution on YOUR website!
Given y = 3x + 11\r
\n" ); document.write( "\n" ); document.write( "3x + 3y = 0\r
\n" ); document.write( "\n" ); document.write( "Plugging in y = 3x + 11 in the above we get,\r
\n" ); document.write( "\n" ); document.write( "3x + 3(3x+11) = 0\r
\n" ); document.write( "\n" ); document.write( "==> 3x + 9x + 33 = 0\r
\n" ); document.write( "\n" ); document.write( "==> 12x + 33 = 0\r
\n" ); document.write( "\n" ); document.write( "==> 12x + 33 - 33 = 0 - 33\r
\n" ); document.write( "\n" ); document.write( "==> 12x = - 33\r
\n" ); document.write( "\n" ); document.write( "==> 12x/12 = - 33/12\r
\n" ); document.write( "\n" ); document.write( "==> x = -11/4\r
\n" ); document.write( "\n" ); document.write( "So y = 3(-11/4) + 11\r
\n" ); document.write( "\n" ); document.write( " = -33/4 + 11\r
\n" ); document.write( "\n" ); document.write( " = (-33+44)/4 [taking LCD and adding]\r
\n" ); document.write( "\n" ); document.write( " = 11/4\r
\n" ); document.write( "\n" ); document.write( "x = - 11/4 and y = 11/4\r
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\n" ); document.write( "\n" ); document.write( "Good Luck!!!
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