document.write( "Question 705655: How many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol? \n" ); document.write( "
Algebra.Com's Answer #434689 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol? \n" ); document.write( "** \n" ); document.write( "let x=amt of 35% alcohol to be mixed \n" ); document.write( "let(40-x)=amt of 60% alcohol to be mixed \n" ); document.write( ".. \n" ); document.write( "35%x+60%(40-x)=53%*40 \n" ); document.write( ".35x+24-.6x=21.2 \n" ); document.write( ".25x=2.8 \n" ); document.write( "x=11.2 \n" ); document.write( "40-x=28.8 \n" ); document.write( "amt of 35% alcohol to be mixed=11.2 liters \n" ); document.write( "amt of 60% alcohol to be mixed=28.8 liters \n" ); document.write( " |