document.write( "Question 705655: How many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol? \n" ); document.write( "
Algebra.Com's Answer #434689 by lwsshak3(11628)\"\" \"About 
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How many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol?
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\n" ); document.write( "let x=amt of 35% alcohol to be mixed
\n" ); document.write( "let(40-x)=amt of 60% alcohol to be mixed
\n" ); document.write( "..
\n" ); document.write( "35%x+60%(40-x)=53%*40
\n" ); document.write( ".35x+24-.6x=21.2
\n" ); document.write( ".25x=2.8
\n" ); document.write( "x=11.2
\n" ); document.write( "40-x=28.8
\n" ); document.write( "amt of 35% alcohol to be mixed=11.2 liters
\n" ); document.write( "amt of 60% alcohol to be mixed=28.8 liters
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