document.write( "Question 705658: $\"%28x-2%29%28x%2B4%29%2Bp=0\"$ . Roots = m,n. m=n, find p \n" ); document.write( "

Algebra.Com's Answer #434684 by josgarithmetic(39620) $\"\"$ $\"About$

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General form x^2+2x+(p-8)=0\r
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\n" ); document.write( "\n" ); document.write( " $\"x=%28-2-sqrt%284-4%28p-8%29%29%29%2F2\"$ OR $\"x=%28-2%2Bsqrt%284-4%28p-8%29%29%29%2F2\"$ \r
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\n" ); document.write( "\n" ); document.write( "Simplifies to
\n" ); document.write( " $\"x=-1-sqrt%28-7-p%29\"$ OR $\"x=-1%2Bsqrt%28-7-p%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "continuing, ... $\"-sqrt%28-7-p%29=sqrt%28-7-p%29\"$ , because both roots are specified as equal
\n" ); document.write( " $\"0=2%2Asqrt%28-7-p%29\"$
\n" ); document.write( " $\"0=4%2A%28-7-p%29\"$
\n" ); document.write( " $\"-28=4p\"$
\n" ); document.write( " $\"highlight%28p=-7%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "x will then be found to be -1, $\"highlight%28x=-1%29\"$ \n" ); document.write( "

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