document.write( "Question 705593: 1) Pat and Sue can paddle a canoe upstream 6 miles in two hours. In the same amount of time they can paddle downstream 14 miles. What is the speed of the current and how fast can they paddle the canoe in still water?
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document.write( "A) Define the variables
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document.write( "B) Write the equations
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document.write( "C) Solve the equations
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document.write( "D) State the answers
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Algebra.Com's Answer #434660 by mananth(16946)![]() ![]() You can put this solution on YOUR website! canoe speed =x mph \n" ); document.write( "current speed =y mph \n" ); document.write( "against current 2 hours \n" ); document.write( "with current 2 hours \n" ); document.write( " \n" ); document.write( "Distance against 6 miles distance with 14 miles \n" ); document.write( "t=d/r against current - \n" ); document.write( "6 / ( x - y )= 2 \n" ); document.write( "2 ( x - y ) = 6 \n" ); document.write( "2 x - 2 y = 6 ....................1 \n" ); document.write( " \n" ); document.write( "14 / ( x + y )= 2 \n" ); document.write( "2 ( x + y ) = 14 \n" ); document.write( "2 x + 2 y = 14 ...............2 \n" ); document.write( "Multiply (1) by 1 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "we get y \n" ); document.write( "2 x + -2 y = 6 \n" ); document.write( "2 x + 2 = 14 \n" ); document.write( "4 x = 20 \n" ); document.write( "/ 4 \n" ); document.write( "x = 5 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) y \n" ); document.write( "2 x -2 y = 6 \n" ); document.write( "10 -2 -10 = 6 \n" ); document.write( "-2 y = 6 \n" ); document.write( "-2 y = -4 mph \n" ); document.write( " y = 2 \n" ); document.write( "canoe speed 5 mph \n" ); document.write( "current speed 2 mph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |