document.write( "Question 705622: Please help me solve this equation:3/n+2/n-1=2 \n" ); document.write( "
Algebra.Com's Answer #434655 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\"%283%2Fn%29%2B2%2F%28n-1%29=2\"\r
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\n" ); document.write( "\n" ); document.write( "LCD is n(n-1)\r
\n" ); document.write( "\n" ); document.write( "multiply the equation by n(n-1)\r
\n" ); document.write( "\n" ); document.write( "we get 3(n-1) +2n = 2n(n-1)\r
\n" ); document.write( "\n" ); document.write( "\"3n-3%2B2n=2n%5E2-2n\"\r
\n" ); document.write( "\n" ); document.write( "re arrange te terms\r
\n" ); document.write( "\n" ); document.write( "\"2n%5E2-7n%2B3=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2n%5E2-6n-n%2B3=0\"\r
\n" ); document.write( "\n" ); document.write( "\"2n%28n-3%29-1%28n-3%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "(2n-1)(n-3)=0\r
\n" ); document.write( "\n" ); document.write( "either 2n-1=0
\n" ); document.write( "or n-3 =0\r
\n" ); document.write( "\n" ); document.write( "2n-1 =0
\n" ); document.write( "2n=1
\n" ); document.write( "n=1/2\r
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\n" ); document.write( "\n" ); document.write( "n-3=0\r
\n" ); document.write( "\n" ); document.write( "n=3\r
\n" ); document.write( "\n" ); document.write( "n=3 OR 1/2\r
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