document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62663>Question 62663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question. What is the average of 3^22, 3^23 and 3^24 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43459 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43459\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given 3^22, 3^23 and 3^24\r<BR>\n" );
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document.write( "We find that the base is same, only the powers are different.\r<BR>\n" );
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document.write( "3^22 + 3^23 +  3^24 = 3^ (22 + 23 + 24)\r<BR>\n" );
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document.write( "                    = 3^ (69)\r<BR>\n" );
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document.write( "THe average is given by the total number divide the number of terms.\r<BR>\n" );
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document.write( "Average = 3 ^ 69 / 3 ^ 3\r<BR>\n" );
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document.write( "Since there are 3 terms.\r<BR>\n" );
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document.write( "Average = 3 ^ (69 / 3)\r<BR>\n" );
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document.write( "        = 3 ^ 23\r<BR>\n" );
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document.write( "Therefore the average is given by 3 ^ 23<BR>\n" );
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