document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=705345>Question 705345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. I am very confused how to solve this with substitution \r<BR>\n" );
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document.write( "-16x+2y=2<BR>\n" );
document.write( "y=8x-1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434527 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint:\r<BR>\n" );
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document.write( "-16x+2y=2 ... start with the first equation\r<BR>\n" );
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document.write( "-16x+2(8x-1)=2 ... plug in y = 8x - 1\r<BR>\n" );
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document.write( "-16x + 16x - 2 = 2 ... distribute\r<BR>\n" );
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document.write( "I'll let you finish </SPAN>\n" );
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