document.write( "Question 705333: at the waters surface, air exerts 1 atmosphere (atm) of pressure. under water, the pressure increases. The pressure P (atm) varies with depth d(ft) according to the equation P=(d/33)+1. Boyles law says the volume V of air varies inversely with the pressure P. If you hold yur breath the volume of air in your lungs increases as you ascend. when have 4 qt air in lungs at a depth of 66 ft (P=3atm), the air will expand to 6 qt when you reach 33 ft, where P=2atm.
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document.write( "* make graph&table to show how volume of air in your lungs varies with depth.
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document.write( "* make table&graph to show how volume of air in lungs varies with pressure.. please help! \n" );
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Algebra.Com's Answer #434512 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the two-point form of an equation of a line to derive the volume as a function of depth equation. The two points being (66,4) and (33,6).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use the two-point form again to derive the volume as a function of pressure equation with the points (3,4) and (2,6).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Two Point Form\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "where \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Once you have done the arithmetic to simplify your equations, a graph and a table is trivial.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |