document.write( "Question 705286: Dave is 4 years older than Billy. Billy is 3 times older than Jon. All three of their ages combined is 39. What is the age of each child?\r
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document.write( "I started the problem by trying to figure out Jon's age. I came up with the answer of 7. That does not add up correctly. It looks the answer should be 5. I need the steps to get to 5. Trying to help my son with this problem last night and I am stumped.\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #434494 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Let B = Billy's Age \n" ); document.write( "Let D = Dave's Age \n" ); document.write( "Let J = Jon's Age \n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "Equation 3: \n" ); document.write( "-------------------------------- \n" ); document.write( "Rewrite equation 2 so that it is solved for J \n" ); document.write( " \n" ); document.write( "Now both equation 1 and equation 2 are in terms of B \n" ); document.write( "Substitue those values into equation 3 for the same letter. \n" ); document.write( "Equation 3: \n" ); document.write( " \n" ); document.write( "Multiply everything by 3 to remove the denominator \n" ); document.write( " \n" ); document.write( "Combine like terms \n" ); document.write( " \n" ); document.write( "Subtract 12 from both sides \n" ); document.write( " \n" ); document.write( "Divide both sides by 7 \n" ); document.write( " \n" ); document.write( "Now plug 15 into the equations 1 and 2 for B. \n" ); document.write( "--------------------------------------------- \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |