document.write( "Question 705215: I am not even sure what topic this problem falls under. It says, \"Find the standard form of the equation of the circle for which the endpoints of a diameter are (0,0)and (4, -6).
\n" ); document.write( "Can you please help me with this?
\n" ); document.write( "Thanks!
\n" ); document.write( "Melissa
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Algebra.Com's Answer #434463 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
If (0,0) and (4,-6) are endpoints of a diameter,
\n" ); document.write( "the midpoint of that diameter is the center of the circle.
\n" ); document.write( "Its coordinates are found by averaging the coordinates of those endpoints.
\n" ); document.write( "The x-coordinate is \"%280%2B4%29%2F2=highlight%282%29\".
\n" ); document.write( "The y-coordinate is \"%280%2B%28-6%29%29%2F2=highlight%28-3%29\"
\n" ); document.write( "So, we have the center, C(2,-3).
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\n" ); document.write( "A picture is work a thousand words:
\n" ); document.write( " The radius, \"R\", is the length of the segment form (0,0) to C(2,-3).
\n" ); document.write( "That segment is the hypotenuse of a right triangle (drawn in green).
\n" ); document.write( "We can calculate \"R%5E2\" based on the Pythagorean theorem
\n" ); document.write( "\"R%5E2=2%5E2%2B3%5E2\" --> \"R%5E2=4%2B9\" --> \"R%5E2=highlight%2813%29\"
\n" ); document.write( "Any point (x,y) in the circle is at the same distance \"R\" from the center, C.
\n" ); document.write( "As a consequence
\n" ); document.write( "\"%28x-2%29%5E2%2B%28y-%28-3%29%29%5E2=R%5E2\" --> \"highlight%28%28x-2%29%5E2%2B%28y%2B3%29%5E2=13%29\"
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