document.write( "Question 705192: Solve the equation. Identify any extraneous solutions. x=√(x+30) \n" ); document.write( "
Algebra.Com's Answer #434442 by josgarithmetic(39618)\"\" \"About 
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Original equation, x=√(x+30).\r
\n" ); document.write( "\n" ); document.write( "Square both sides: x^2=x+30. Adjust into general form:
\n" ); document.write( "x^2-x-30=0
\n" ); document.write( "Factor it? (x-6)(x+5)=0.
\n" ); document.write( "Solutions possible are x=+6 or x=-5. One of these may be \"extraneous\" and will not work in the original equation of x=√(x+30).\r
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\n" ); document.write( "\n" ); document.write( "Check +6:
\n" ); document.write( "6=sqrt(6+30)? Yes. Because 6*6=36.\r
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\n" ); document.write( "\n" ); document.write( "Check -5:
\n" ); document.write( "5=sqrt(-5+30)? 5=sqrt(+25)? Yes. This too works. \r
\n" ); document.write( "\n" ); document.write( "Solution is then \"highlight%28x=-5%29\" or \"highlight%28x=%2B6%29\".
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