document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=705126>Question 705126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A side of a square is (3+2x). The area is 1.69 cm squared. What is the value of x? \r<BR>\n" );
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document.write( "Thank you in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434422 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A side of a square is (3+2x). The area is 1.69 cm squared. What is the value of x? <BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283+%2B+2x%29%5E2+=+1.69 ALIGN=MIDDLE  ALT=\"%283+%2B+2x%29%5E2+=+1.69\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "3 + 2x = 1.3<BR>\n" );
document.write( "2x = -1.7<BR>\n" );
document.write( "x = -0.85<BR>\n" );
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document.write( "Or,<BR>\n" );
document.write( "3 + 2x = -1.3<BR>\n" );
document.write( "2x = -4.3<BR>\n" );
document.write( "x = -2.15<BR>\n" );
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