document.write( "Question 705115: Please can someone help me with this question!! thanks\r
\n" ); document.write( "\n" ); document.write( "If x<0 and y >O Determine the sign.
\n" ); document.write( "1.a)xy^2 divided by y
\n" ); document.write( "b) 1-x^2 divided by 1-y\r
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Algebra.Com's Answer #434419 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
1a)\r
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\n" ); document.write( "\n" ); document.write( "x < 0, so x is negative\r
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\n" ); document.write( "\n" ); document.write( "y > 0, so y is positive\r
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\n" ); document.write( "\n" ); document.write( "This means y^2 is positive and so is y^2 divided by y\r
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\n" ); document.write( "\n" ); document.write( "Multiply this positive number (y^2 divided by y) with a negative number (x) to get\r
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\n" ); document.write( "\n" ); document.write( "xy^2 over y\r
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\n" ); document.write( "\n" ); document.write( "and this result will be negative since negative times positive = negative.\r
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\n" ); document.write( "\n" ); document.write( "1b)\r
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\n" ); document.write( "\n" ); document.write( "x^2 is always positive regardless if x is positive or negative\r
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\n" ); document.write( "\n" ); document.write( "1 - x^2 is positive only if x^2 < 1 or if -1 < x < 1\r
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\n" ); document.write( "\n" ); document.write( "1 - y is positive only if y < 1\r
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\n" ); document.write( "\n" ); document.write( "Since x < 0, we know for a fact that 1 - x^2 is negative (see the rule above)\r
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\n" ); document.write( "\n" ); document.write( "Because y > 0, we know that 1-y is negative (again, look at the rule)\r
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\n" ); document.write( "\n" ); document.write( "So 1-x^2 is negative when x < 0 and 1-y is negative when y > 0\r
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\n" ); document.write( "\n" ); document.write( "Therefore 1-x^2 divided by 1-y is positive (negative/negative = positive)
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