document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704977>Question 704977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer for log(2x+1) = 1 + log (x-2) ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434374 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39623)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Steps:<BR>\n" );
document.write( "log(2x+1)-log(x-2)=1 <BR>\n" );
document.write( "log((2x+1)/(x-2))=1  [property of logarithms]\r<BR>\n" );
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document.write( "You need to know which base to continue.  Is the base 10, or 2, or e?  If base is 10, then  (2x+1)/(x-2)=10, <BR>\n" );
document.write( "2x+1=10x-20,<BR>\n" );
document.write( "1=8x-20<BR>\n" );
document.write( "-19=8x,<BR>\n" );
document.write( "x=-19/8\r<BR>\n" );
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document.write( "Is base 2?<BR>\n" );
document.write( "(2x+1)=2(x-2)<BR>\n" );
document.write( "2x+1=2x-4<BR>\n" );
document.write( "False\r<BR>\n" );
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document.write( "Is the base e? </SPAN>\n" );
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