document.write( "Question 704830: \r
\n" ); document.write( "\n" ); document.write( "A rectangle is 6 times as long as it is wide. The area is 54 square feet. What is the perimeter of the rectangle?
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Algebra.Com's Answer #434353 by checkley79(3341)\"\" \"About 
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L=6W
\n" ); document.write( "A=LW
\n" ); document.write( "54=6W*W
\n" ); document.write( "54=6W^2
\n" ); document.write( "W^2=54/6
\n" ); document.write( "W^2=9
\n" ); document.write( "W=SQRT9
\n" ); document.write( "W=3 ANS. FOR THE WIDTH.
\n" ); document.write( "L=6*3=16 ANS. FOR THE LENGTH.
\n" ); document.write( "P=2L+2W
\n" ); document.write( "P=2*16+2*3
\n" ); document.write( "P=32+6=42 ANS. FOR THE PERIMETER.
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