document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704904>Question 704904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "mary is y year old.her father is 4 times older then mary.her mother is 7 years younger than her father.if their three ages add up to 101 years,find the value of y. find the ages of mary's parents </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434315 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> MARY=Y<BR>\n" );
document.write( "FATHER=4Y<BR>\n" );
document.write( "MOTHER=4Y-7<BR>\n" );
document.write( "Y+4Y+4Y-7=101<BR>\n" );
document.write( "9Y=101+7<BR>\n" );
document.write( "9Y=108<BR>\n" );
document.write( "Y=108/9<BR>\n" );
document.write( "Y=12 AGE OF THE DAUGHTER.<BR>\n" );
document.write( "4*12=48 AGE OF THE FATHER.<BR>\n" );
document.write( "48-7=41 AGE OF THE MOTHER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12+48+41=101<BR>\n" );
document.write( "101=101<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );