document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704890>Question 704890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the digits 2, 3, 5 and 7 so the product is 945.  need to show work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434314 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No.  You cannot use 2.  If 2 is a factor, the product WILL be even.  Any integer ending in 5 is odd.  Try completely factoring 945 and you will see.  You first find 5*9*21, and then..., 5*3*3*3*7.  There is no \"2\" and there is no \"7\". </SPAN>\n" );
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