document.write( "Question 704897: When the sum of 618 and three times a positive number is subtracted from the square of the number, the result is 136. Find the number. \n" ); document.write( "
Algebra.Com's Answer #434308 by josgarithmetic(39618)\"\" \"About 
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n is a number;
\n" ); document.write( "618+3n,
\n" ); document.write( "When -(618+3n)+n^=136.\r
\n" ); document.write( "\n" ); document.write( "n^2-3n-618=136
\n" ); document.write( "n^2-3n-618-136=0
\n" ); document.write( "n^2-3n-754=0\r
\n" ); document.write( "\n" ); document.write( "\"n=%283%2Bsqrt%289-4%2A%28-754%29%29%29%2F2\" or \"n=%283-sqrt%289-4%2A%28-754%29%29%29%2F2\", only one of them would work.
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