document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704834>Question 704834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When the sum of 546 and three times a positive number is subtracted from the square of the number, the result is 154. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434300 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     When the sum of 546 and three times a positive number is subtracted from the square of the number, the result is 154. Find the number.<BR>\n" );
document.write( "Let n = the number<BR>\n" );
document.write( "then<BR>\n" );
document.write( "n^2 - (546 + 3n) = 154<BR>\n" );
document.write( "n^2 - 546 - 3n = 154<BR>\n" );
document.write( "n^2 - 3n - 546 = 154<BR>\n" );
document.write( "n^2 - 3n - 700 = 0<BR>\n" );
document.write( "(n + 25)(n - 28) = 0<BR>\n" );
document.write( "n = {-25, 28}<BR>\n" );
document.write( "Since the problem specified a POSITIVE number:<BR>\n" );
document.write( "n = 28 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );