document.write( "Question 704816: Please help me!!!! \r
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document.write( "A store is selling two different types of cheese. One type sells for $3.75 a pound and a second type sells for $4.55 a pound. How many pounds of the $3.75 cheese would the store need to mix together with the $4.55 cheese to get a 45-pound block mixture that sells for $4.05 a pound?
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document.write( "Thank you so much! :D
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Algebra.Com's Answer #434283 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Let A = pounds of cheese that costs $3.75/pound \n" ); document.write( "Let B = pounds of cheese that costs $4.55/pound \n" ); document.write( "Equation 1: \n" ); document.write( "Equation 2: \n" ); document.write( "------------------------------------------ \n" ); document.write( "Solve Equation 1 for one of the variables. \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( "Now plug (45 - B) into Equation 2 for A \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "Multiply the 3.75 trough and simplify the equation \n" ); document.write( " \n" ); document.write( "Multiply both sides by 45 \n" ); document.write( " \n" ); document.write( "Combine like terms \n" ); document.write( " \n" ); document.write( "Subtract 168.75 from both sides \n" ); document.write( " \n" ); document.write( "Divide both sides by 0.8 \n" ); document.write( " \n" ); document.write( "Now plug 16.875 into equation 1 for B \n" ); document.write( "Equation 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |