document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=704695>Question 704695</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I hope this is the right place.  Can you help?  Here are the problem:s<BR>\n" );
document.write( "Question # 1:\r<BR>\n" );
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document.write( "Identify the system as consistent or inconsistent, and dependent or independent.<BR>\n" );
document.write( "3x - 9y=6<BR>\n" );
document.write( "y=1/3x - 2/3\r<BR>\n" );
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document.write( "Question # 2:<BR>\n" );
document.write( " A chemist has prepared two acid solutions, one which is 6% acid by volume and the other which is 10% acid. How many cubic centimeters of each should the chemist mix together to obtain 50 cm3 of 7.28% acid solution?\r<BR>\n" );
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document.write( "Question #3. Solve using any appropriate method.  0.1x + 0.5y=2<BR>\n" );
document.write( "                                                  0.5x - 0.1y=1\r<BR>\n" );
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document.write( "If the system has an infinate number of solutions, use set builder notations to write th esolution set. If the system has no solution, state this.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #434244 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=434244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Question #2, the acid mixture:\r<BR>\n" );
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document.write( "x and y, the volume of low and high concentration acids<BR>\n" );
document.write( "Solve this system:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By=50 ALIGN=MIDDLE  ALT=\"x%2By=50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2A0.06%2By%2A0.10%29%2F50=0.0728 ALIGN=MIDDLE  ALT=\"%28x%2A0.06%2By%2A0.10%29%2F50=0.0728\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The rational one rearranges to 6x+10y=50*7.28, then 6x+10y=364, then 3x+5y=182<BR>\n" );
document.write( "So an easier but equivalent system to solve is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2By=50 ALIGN=MIDDLE  ALT=\"x%2By=50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%2B5y=182 ALIGN=MIDDLE  ALT=\"3x%2B5y=182\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You might continue by taking the x+y=50 and multiply both sides by 3, and subtracting the equation from the \"182\" equation, and find a value for y.  \r<BR>\n" );
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document.write( "3x+5y=182<BR>\n" );
document.write( "-(3x+3y)=-(150)<BR>\n" );
document.write( "________________<BR>\n" );
document.write( "0+2y=32<BR>\n" );
document.write( "y=16.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=16%29 ALIGN=MIDDLE  ALT=\"highlight%28y=16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cubic centimeter for the 10% acid, so.... </SPAN>\n" );
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