document.write( "Question 704685: Ok this is a parabola question.\r
\n" ); document.write( "\n" ); document.write( "What are the zeros for the equation y=-2x^2+5x+3\r
\n" ); document.write( "\n" ); document.write( "The vertex form is y=-2(x-5/4)^2 +49/8. \r
\n" ); document.write( "\n" ); document.write( "This seems like a very difficult problem, and I sure can't figure it out. Any help would be greatly appreciated! Thanks sooo much!!!
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Algebra.Com's Answer #434237 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
What are the zeros for the equation y=-2x^2+5x+3
\n" ); document.write( ".
\n" ); document.write( "The \"zeros\" are the \"roots\" of the quadratic -- or, where it crosses the x-axis.
\n" ); document.write( "So, you basically set y equal to zero and solve for x:
\n" ); document.write( "given:
\n" ); document.write( "y=-2x^2+5x+3
\n" ); document.write( "setting y to zero:
\n" ); document.write( "0=-2x^2+5x+3
\n" ); document.write( "multiplying both sides by -1:
\n" ); document.write( "0=2x^2-5x-3
\n" ); document.write( "factoring the right side:
\n" ); document.write( "0=(2x+1)(x-3)
\n" ); document.write( "x = {-1/2, 3} (zeros)
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